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Plastic injection molding cost - EuroPlas - low volume injection molding cost

Author:gly    Date: 2024-10-15    

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For a pump pressure of 75kg/cm^2, an effective injection cylinder area of 150cm^2, and a screw cross-sectional area of 15.9cm^2 (for a diameter of 45mm), the injection pressure is: Pi = (75 x 150) / 15.9 = 707 kg/cm^2

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Actual Hourly Power Consumption (KW/Hr) = (Motor Capacity + Electric Heating Capacity + Dryer Capacity) x Power Usage Constant (approx. 40%).

For a motor speed of 1000RPM, a pump discharge volume of 85 cc/RPM, and an effective injection cylinder area of 140 cm^2, the injection speed is: S = (85 x 1000) / (60 x 140) = 10.1 cm/sec

For a screw diameter of 42mm and an injection stroke of 165mm, the injection volume is: V = π x (4.2/2)^2 x 16.5 = 228.6cm^3

Product Layout Projection Area (in²) x Standard Thickness (1.5mm) / Average Product Thickness (mm) x Material Constant / PS Material Constant (1) = Clamping Force (Ton).

For instance, if the mold cavity projected area is 270cm^2 and the filling pressure is 220kg/cm^2, the clamping force is: F = (270 x 220) / 1000 = 59.4TON

These formulas offer a foundational grasp of the pivotal parameters in injection molding, ensuring optimal results in the molding process.

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Given an injection volume of 228.6cm^3, a mechanical efficiency of 0.85, and a specific gravity of 0.92, the injection weight is: Vw = 228.6 x 0.85 x 0.92 = 178.7g

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